mysql_fetch_row

(PHP 4, PHP 5, PECL mysql:1.0)

mysql_fetch_row — Devuelve una fila de resultado como matriz

Descripción

array mysql_fetch_row ( int $id_resultado )

Devuelve: Una matriz que corresponde a la fila selecionada, o FALSE si no quedan más filas.

Note: Esta funcion define campos NULL como valores PHP NULL.

mysql_fetch_row() seleciona una fila de datos del resultado asociado al identificador de resultado especificado. La fila es devuelta como una matriz. Cada columna del resultdo es guardada en un offset de la matriz, empezando por el offset 0.

La llamada a mysql_fetch_row() debería devolver la próxima fila del resultado, o FALSE si no quedan más filas.

Example #1 Ejemplo de mysql_fetch_row


<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
    echo 'Could not run query: ' . mysql_error();
    exit;
}
$row = mysql_fetch_row($result);

echo $row[0]; // 42
echo $row[1]; // the email value
?>

Ver también: mysql_fetch_array(), mysql_fetch_object(), mysql_data_seek(), mysql_fetch_lengths(), mysql_result().

mysql_field_flags

mysql_fetch_object

Last updated: Fri, 22 Aug 2008

add a note User Contributed Notes
mysql_fetch_row

larkitetto at gmail dot com
21-Feb-2008 05:29


sry :) note now fixed:



<?php

$esi=mysql_list_tables($db);$ris=mysql_fetch_row($esi);

//example: $db has >= 1 tabs

echo var_dump($ris);

//echoes only array(1). solution:

while($ris=mysql_fetch_row($esi)) echo $ris[0];

/*debug:

$ris=array("1st_tab"); ... $ris=array("n_tab");$ris=false;*/

while ($ris[]=mysql_fetch_row($esi));

//debug:$ris=array(array("1st_tab"), ... array("n_tab"));

echo $ris[n][0];//echo:"n_tab"

echo $ris[0][n];//echo:array | null

?>



hope it helps

ryhan_balboa at yahoo dot com
16-Nov-2007 11:23


The following are the basic codes to get a specific row from the mysql db into a $row variable:



 

$query = "SELECT * FROM table"; 

$result = mysql_query($query); 

$row = mysql_fetch_row($result);



And $row[0], $row[1] ... $row[n] are used to access those field values. 



Does anyone know how I can add a new field to $row, so that the field count increases from n to n+1?



I have tried treating $row like an array, and tried array_push function, but didn't work.



Thanks.

m dot s at programmers-online dot net
17-Nov-2005 03:56


The following function to read all data out of a mysql-resultset, is may be faster than Rafaels solution:



<?

function mysql_fetch_all($result) {

   while($row=mysql_fetch_array($result)) {

       $return[] = $row;

   }

   return $return;

}

?>

mysql at polyzing dot com
12-Jul-2003 05:05


It is probably worth pointing out that the array elements will actually be of type string, OR NULL if the field is null in the database.



Thus, either use a double equal comparison to look for empty or null



Or, use a triple equal comparison to be able to distinguish the two cases



e.g.



if ($field === '') echo "Empty, not NULL\n";



if ($field === NULL) echo "NULL\n";



if ($field == '') echo "Empty or NULL\n";

michael and then an at sign wassupy.com
08-Apr-2003 02:09


to print an array, simply use print_r(array name)



like this:

    $myrow = mysql_fetch_row($result);

echo "<pre>";

print_r($myrow);

echo "</pre>";



this will output the array in a readable form, with the index, too. Don't forget the 'pre' tags or the output will be on a single line.

a at simongrant dot org
06-Feb-2002 07:10


Maybe worth pointing out that all the fields returned by this (and other?) calls are returned with type string. This had me puzzled for quite some time.

add a note

mysql_field_flags

mysql_fetch_object

Last updated: Fri, 22 Aug 2008